In a ∆ PQR, if 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P=1, then the angle R is equal to
Mathematics · JEE Main · NTA Exams — Trigonometry
In a ∆ PQR, if 3 sin P + 4 cos Q = 6 and
4 sin Q + 3 cos P=1, then the angle R is equal to
4 sin Q + 3 cos P=1, then the angle R is equal to
- \(\frac{5 \pi}{6}\)
- \(\frac{\pi}{6}\)
- \(\frac{\pi}{4}\)
- \(\frac{3 \pi}{4}\)
Answer
(B) 6
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