Distance between two parallel planes 2 x+y+2 z=8 and 4 x+2 y+4 z+5=0 is
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
Distance between two parallel planes \(2 x+y+2 z=8 \text { and } 4 x+2 y+4 z+5=0\) is
- \(\frac{3}{2}\)
- \(\frac{5}{2}\)
- \(\frac{7}{2}\)
- \(\frac{9}{2}\)
Answer
(C) 7 2
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