Distance between two parallel planes 2 x+y+2 z=8 and 4 x+2 y+4 z+5=0 is

Mathematics · JEE Main · NTA ExamsThree Dimensional Geometry

Distance between two parallel planes \(2 x+y+2 z=8 \text { and } 4 x+2 y+4 z+5=0\) is
  1. \(\frac{3}{2}\)
  2. \(\frac{5}{2}\)
  3. \(\frac{7}{2}\)
  4. \(\frac{9}{2}\)

Answer

(C) 7 2

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