Let f ( x ) = (1+ b 2 ) x 2 + 2 bx + 1 and let m ( b ) be the minimum value of f ( x )…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
Let f (x) = (1+b2)x2 + 2bx + 1 and let m (b) be the minimum value of f (x). As b varies, the range of m(b) is in
- (0, 1]
- [0, 1/2]
- [1/2, 1]
- [0, 1].
Answer
(C) [1/2, 1]
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