For the reaction 2NH 3 → N 2 + 3H 2 , if - d [ NH _ 3 ] d t =k_ 1 [ NH _ 3 ], d [ ~N _ 2…
Chemistry · Class 12 · CBSE — Chemical Kinetics
For the reaction 2NH3 → N2 + 3H2, if
\(-\frac{d\left[\mathrm{NH}_{3}\right]}{d t}=k_{1}\left[\mathrm{NH}_{3}\right], \frac{d\left[\mathrm{~N}_{2}\right]}{d t}=k_{2}\left[\mathrm{NH}_{3}\right] \frac{d\left[\mathrm{H}_{2}\right]}{d t}=k_{3}\left[\mathrm{NH}_{3}\right]\)
then the relation between k1, k2 and k3 is
\(-\frac{d\left[\mathrm{NH}_{3}\right]}{d t}=k_{1}\left[\mathrm{NH}_{3}\right], \frac{d\left[\mathrm{~N}_{2}\right]}{d t}=k_{2}\left[\mathrm{NH}_{3}\right] \frac{d\left[\mathrm{H}_{2}\right]}{d t}=k_{3}\left[\mathrm{NH}_{3}\right]\)
then the relation between k1, k2 and k3 is
- k1 = k2 = k3
- k1 = 3k2 = 2k3
- 1.5k1 = 3k2 = k3
- 2k1 = k2 = 3k3.
Answer
(C) 1.5 k 1 = 3 k 2 = k 3
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