The decomposition of a hydrocarbon follows the equation k = (4.5 × 10 11 s –1 ) e –28000…
Chemistry · Class 12 · CBSE — Chemical Kinetics
The decomposition of a hydrocarbon follows the equation k = (4.5 × 1011 s–1)e–28000 K/T. What will be the value of activation energy?
- 669 kJ mol–1
- 232.79 kJ mol–1
- 4.5 × 1011 kJ mol–1
- 28000 kJ mol–1
Answer
(B) 232.79 kJ mol –1
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