The fourth, seventh and tenth terms of a G.P. are p, q, r respectively, then
Mathematics · JEE Main · NTA Exams — Progression and Series
The fourth, seventh and tenth terms of a G.P. are p, q, r respectively, then
- \(\mathrm{p}^{2}=\mathrm{q}^{2}+\mathrm{r}^{2}\)
- \(\mathrm{q}^{2}=\mathrm{pr}\)
- \(\mathrm{p}^{2}=\mathrm{qr}\)
- pqr + pq + 1 = 0
Answer
(B) q ^ 2 = pr
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The sum of first ten terms of an AP is four times the sum of its first five terms, then ratio of first term…
- The product of three numbers in GP is 125 and sum of their product taken in pairs is 87 1 2 . Find the…
- Let a_ 1 , a_ 2 , a_ 3 , ., a_ n be a GP such that a _ 4 a _ 6 = 1 4 and a_ 2 +a_ 5 =216 . Then integral…
- _ n=0 ^ ( _ e x )^ n n! is equal to
- The sum to n terms of the series 1 1.3 + 1 3.5 + 1 5.7 + ..... is
- If the sum of first two terms of an infinite GP is 1 and every term is twice the sum of all the successive…
- For what value of m, a ^ m+1 + b ^ m+1 a ^ m + b ^ m is the arithmetic mean of 'a' and 'b' ?
- n arithmetic means are inserted in between x and 2y and then between 2x and y. In case the r th mean in both…
More Progression and Series questions · Browse all practice questions