_ - 2 ^ 2 ^ 2 x ^ 5 x d x equals
Mathematics · JEE Main · NTA Exams — Integral Calculus
\[\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} \sin ^{2} x \cdot \cos ^{5} x d x\] equals
- \(\frac{1}{20}\)
- 20
- 0
- \(\frac{1}{330}\)
Answer
(C) 0
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