_ n [ 1 n^ 2 ^ 2 1 n^ 2 + 2 n^ 2 ^ 2 4 n^ 2 + + 1 n ^ 2 1 ] equals
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\lim _{n \rightarrow \infty}\left[\frac{1}{n^{2}} \sec ^{2} \frac{1}{n^{2}}+\frac{2}{n^{2}} \sec ^{2} \frac{4}{n^{2}}+\ldots+\frac{1}{n} \sec ^{2} 1\right]\)equals
- \(\frac{1}{2} \cos \mathrm{e} 1\)
- \(\frac{1}{2} \sec 1\)
- \(\frac{1}{2} \tan 1\)
- tan 1
Answer
(C) 1 2 1
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