The equation of the circle passing through (1, –3) & the points common to the two circle…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the circle passing through (1, –3) & the points common to the two circle,
x2 + y2 – 6x + 8y – 16 = 0, x2 + y2 + 4x – 2y – 8 = 0 is.
x2 + y2 – 6x + 8y – 16 = 0, x2 + y2 + 4x – 2y – 8 = 0 is.
- x2 + y2 – 4x + 6y + 24 = 0
- 2x2 + 2y2 + 3x + y – 20 = 0
- 3x2 + 3y2 – 5x + 7y – 19 = 20
- none of these
Answer
(B) 2x 2 + 2y 2 + 3x + y – 20 = 0
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