For the reaction Zn(s) + Cu 2+ (aq) ⇌ Cu(s) + Zn 2+ (aq) Reaction Quotient = [ Zn ^ 2+ ]…

For the reaction
Zn(s) + Cu²⁺ (aq) \(\text { ⇌ }\) Cu(s) + Zn²⁺ (aq)
Reaction Quotient = \(\frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cu}^{2+}\right]},\) variation of E_cell with Q is given by
(where Q = concentration quotient)
 
OA = 1.10 volts, hence
When E_cell is 1.1591 and concentration ratio is, \(\frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cu}^{2+}\right]}=10^{-2}\) it implies,