For a cell reaction involving a two-electron change, the standard e.m.f. of the cell is…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
For a cell reaction involving a two-electron change, the standard e.m.f. of the cell is found to be 0.295V at 25ºC. The equilibrium constant of the reaction at 25ºC will be
- 1 × 10–10
- 29.5 × 10–2
- 10
- 1 × 1010
Answer
(D) 1 × 10 10
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A 4.0 M aqueous solution of NaCl is prepared and 500 mL of this solution is electrolysed. This leads to the…
- The conductance of 0.1 M HCl solution is greater than that of 0.1 M NaCl. This is because
- The EMF of the cell, Zn | Zn 2+ (0.01 M) || Fe 2+ (0.001M) | Fe at 298 K is 0.2905 then the value of…
- Tollen’s reagent is used for the detection of aldehydes. When a solution of AgNO 3 is added to glucose with…
- Which of the following reaction occurs at the anode during the charging of lead storage battery ?
- During the electrolysis of aqueous sodium chloride, the cathodic reaction is
- The resistance of 0.1 N solution of a salt is found to be 2.5 × 10 3 ohm. The equivalent conductance of the…
- A gas X at 1 atm is bubbled through a solution containing a mixture of 1M Y – and 1 M Z – at 25ºC. If the…
More Electrochemistry questions · Browse all practice questions