Limit _ x -1 2- 2 x x^ 2 -|x| =

Mathematics · JEE Advanced · NTA ExamsLimit, Continuity and Differentiability

\(\operatorname{Limit}_{x \rightarrow-1} \frac{\cos 2-\cos 2 x}{x^{2}-|x|}=\)
  1. 2 cos 2
  2. – 2 cos 2
  3. 2 sin 2
  4. – 2 sin 2

Answer

(C) 2 sin 2

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