Limit _ x -1 2- 2 x x^ 2 -|x| =
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
\(\operatorname{Limit}_{x \rightarrow-1} \frac{\cos 2-\cos 2 x}{x^{2}-|x|}=\)
- 2 cos 2
- – 2 cos 2
- 2 sin 2
- – 2 sin 2
Answer
(C) 2 sin 2
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