A mixture of weak acid is 0.1 M in HCOOH (K a = 1.8 × 10 –4 ) and 0.1 M in HOCN (Ka = 3.1…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
A mixture of weak acid is 0.1 M in HCOOH
(Ka = 1.8 × 10–4) and 0.1 M in HOCN (Ka = 3.1 × 10–4). Hence, \(\left[\mathrm{H}_{3} \mathrm{O}^{\oplus}\right]\) is
(Ka = 1.8 × 10–4) and 0.1 M in HOCN (Ka = 3.1 × 10–4). Hence, \(\left[\mathrm{H}_{3} \mathrm{O}^{\oplus}\right]\) is
- 7.0 × 10–3 M
- 4.1 × 10–4 M
- 0.20 M
- 4.1 × 10–3 M
Answer
(A) 7.0 × 10 –3 M
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