During the titration of weak diprotic acid H 2 A against strong base NaOH, the pH of the…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
During the titration of weak diprotic acid H2A against strong base NaOH, the pH of the solution half-way to the first equivalence point and that at first equivalence point are given respectively by :
- \(\mathrm{pK}_{\mathrm{a}_{1}}\) and \(\mathrm{pK}_{\mathrm{a}_{2}}\)
- \(\mathrm{pK}_{\mathrm{a}_{1}}\) and \(\frac{\mathrm{pK}_{a_{1}}+\mathrm{pK}_{\mathrm{a}_{2}}}{2}\)
- pKa and \(\left(\mathrm{pK}_{\mathrm{a}_{1}}+\mathrm{pK}_{\mathrm{a}_{2}}\right)\)
- \(\sqrt{\mathrm{CK}_{\mathrm{a}_{1}}}\) and\(\frac{\mathrm{pK}_{a_{1}}+\mathrm{pK}_{\mathrm{a}_{2}}}{2}\)
Answer
(B) pK _ a _ 1 and pK _ a_ 1 + pK _ a _ 2 2
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