Equilibrium constant for two complexes are : A : K 4 [Fe(CN) 6 ] K=2.6 × 10 37 (for…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
Equilibrium constant for two complexes are :
A : K4 [Fe(CN)6] K=2.6 × 1037 (for dissociation)
B : K3 [Fe(CN)6] K=1.9 × 1017 (for dissociation)
A : K4 [Fe(CN)6] K=2.6 × 1037 (for dissociation)
B : K3 [Fe(CN)6] K=1.9 × 1017 (for dissociation)
- A and B are equally stable
- A is more stable than B
- B is more stable than A
- the predictable stability
Answer
(C) B is more stable than A
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