For the reversible reaction, N 2 (g) + 3H 2 (g) ⇌ 2NH 3 (g) at 500ºC, the value of K p is…

Chemistry · JEE Advanced · NTA ExamsEquilibrium

For the reversible reaction, N2(g) + 3H2(g) \(\text { ⇌ }\)2NH3(g) at 500ºC, the value of Kp is 1.44 × 10–5 when partial pressure is measured in atmospheres. The corresponding value of Kc, with concentration in mole litre–1 is (2000)
  1. \[\frac{1.44 \times 10^{-5}}{(0.082 \times 500)^{-2}}\]
  2. \(\frac{1.44 \times 10^{-5}}{(8.314 \times 773)^{-2}}\)
  3. \(\frac{1.44 \times 10^{-5}}{(0.082 \times 773)^{2}}\)
  4. \(\frac{1.44 \times 10^{-5}}{(0.082 \times 773)^{-2}}\)

Answer

(D) 1.44 10^ -5 (0.082 773)^ -2

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