The function f(x)= array ll |x-3| & , x 1 x^ 2 4 - 3 x 2 + 13 4 & , x<1 array . .
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
The function \[f(x)=\left\{\begin{array}{ll}
|x-3| & , x \geq 1 \\
\frac{x^{2}}{4}-\frac{3 x}{2}+\frac{13}{4} & , x<1
\end{array}\right.\].
- continuous at x = 1
- differentiable at x = 1
- continuous at x = 3
- differentiable at x = 3
Answer
(A) continuous at x = 1
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