If f(x)= aligned 3 x^ 2 +12 x-1, & -1 x 2 37-x, & 2<x 3 aligned .
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
If \(f(x)=\left\{\begin{aligned}
3 x^{2}+12 x-1, & -1 \leq x \leq 2 \\
37-x, & 2
- f (x) is increasing on [–1, 2]
- f (x) is continuous on [–1, 3]
- f′(2) does not exist
- f (x) has the maximum value at x = 2
Answer
(C) f ′ (2) does not exist
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