If f(x)= aligned 3 x^ 2 +12 x-1, & -1 x 2 37-x, & 2<x 3 aligned .

Mathematics · JEE Advanced · NTA ExamsLimit, Continuity and Differentiability

If \(f(x)=\left\{\begin{aligned} 3 x^{2}+12 x-1, & -1 \leq x \leq 2 \\ 37-x, & 2
  1. f (x) is increasing on [–1, 2]
  2. f (x) is continuous on [–1, 3]
  3. f(2) does not exist
  4. f (x) has the maximum value at x = 2

Answer

(C) f ′ (2) does not exist

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