Limit _ x 5 x^ 2 -9 x+20 x-[x] where [x] is the greatest integer not greater than x
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
\(\operatorname{Limit}_{x \rightarrow 5} \frac{x^{2}-9 x+20}{x-[x]}\) where [x] is the greatest integer not greater than x
- is equal to 1
- 0
- 4
- none
Answer
(D) none
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