Let the line y = mx and the ellipse 2 x^ 2 +y^ 2 =1 intersect at a point P in the first…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Let the line y = mx and the ellipse \(2 x^{2}+y^{2}=1\) intersect at a point P in the first quadrant. If the normal to this ellipse at P meets the co-ordinate axes at \(\left(-\frac{1}{3 \sqrt{2}}, 0\right)\) and \((0, \beta)\), then β is equal to :
- \(\frac{2}{\sqrt{3}}\)
- \(\frac{\sqrt{2}}{3}\)
- \(\frac{2}{3}\)
- \(\frac{2 \sqrt{2}}{3}\)
Answer
(C) 2 3
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