The two curves y 2 = 4x and x 2 + y 2 – 6x + 1 = 0 at the point (1, 2)
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The two curves y2 = 4x and x2 + y2 – 6x + 1 = 0 at the point
(1, 2)
(1, 2)
- intersect orthogonally
- intersect at an angle \(\frac{\pi}{3}\)
- touch each other
- none of these
Answer
(C) touch each other
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