Let y = a x + bx be curve, (2x – y) + λ (2x + y – 4) = 0 be family of lines. A line of…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Let y = a \(\sqrt{\mathrm{x}}\) + bx be curve, (2x – y) + λ (2x + y – 4) = 0 be family of lines.
A line of the family cutting positive intercepts on axes and forming triangle with coordinate axes, then minimum length of the line segment between axes is
- (22/3 – 1)3/2
- (22/3 + 1)3/2
- 73/2
- 27
Answer
(B) (2 2/3 + 1) 3/2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let f (x) = [ array ll x^ 3 -x^ 2 +10 x-5, & x 1 -2 x+ _ 2 (b^ 2 -2 ), & x>1 array . the set of values of b…
- If y = a cos ( l og x) + b sin ( l og x) where a, b are parameters, the x 2 y′′ + xy′ is equal to
- If f (x) is a differentiable function and φ (x) is twice differentiable function and α and β are roots of the…
- If (x – a) 2n (x –b) 2m +1 , where m and n are positive integers and a > b, is the derivative of a function f…
- _ n a ^ n +b^ n a ^ n -b^ n where a>b>1 is equal to
- If f (x) = l og |x|, x ≠ 0 then f ′(x) equals
- The sub-tangent at any point of the curve x m y n = a m + n varies as
- _ x 1 1-x^ -2 / 3 1-x^ -1 / 3 is equal to
More Limit, Continuity and Differentiability questions · Browse all practice questions