Complete solution set of the equation |x 2 – 1 + cos x| = |x 2 – 1| + |cos x| belonging…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
Complete solution set of the equation
|x2 – 1 + cos x| = |x2 – 1| + |cos x|
belonging to (–2π, π) is
|x2 – 1 + cos x| = |x2 – 1| + |cos x|
belonging to (–2π, π) is
- \(\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \cup(-1,1)\)
- \(\left[-\frac{3 \pi}{2}, \frac{\pi}{2}\right] \cup[-1,1] \cup\left[\frac{\pi}{2}, \pi\right)\)
- \(\left[-\frac{3 \pi}{2},-\frac{\pi}{2}\right] \cup\left[\frac{\pi}{2}, \pi\right)\)
- \(\left(-2 \pi, \frac{-3 \pi}{2}\right] \cup\left[-\frac{\pi}{2},-1\right] \cup\left[1, \frac{\pi}{2}\right]\)
Answer
(D) (-2 , -3 2 ] [- 2 ,-1 ] [1, 2 ]
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