For positive integer n , define + 48-3 n-3 n^ 2 12 n+3 n^ 2 + + 25 n-7 n^ 2 7 n^ 2 Then…
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
For positive integer n, define
\(+\frac{48-3 n-3 n^{2}}{12 n+3 n^{2}}+\ldots+\frac{25 n-7 n^{2}}{7 n^{2}}\)
Then, the value of \(\lim _{n \rightarrow \infty} f(n)\) is equal to
\(+\frac{48-3 n-3 n^{2}}{12 n+3 n^{2}}+\ldots+\frac{25 n-7 n^{2}}{7 n^{2}}\)
Then, the value of \(\lim _{n \rightarrow \infty} f(n)\) is equal to
Answer
(B)
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