If y=e^ ^ -1 x and u = l og x, then dy du is
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If \(y=e^{\sin ^{-1} x}\) and u = log x, then \(\frac{\mathrm{dy}}{\mathrm{du}}\)is
- \[\frac{e^{\sin ^{-1} x}}{\sqrt{1-x^{2}}}\]
- \(x e^{\sin ^{-1} x}\)
- \[\frac{\mathrm{xe}^{\sin ^{-1} \mathrm{x}}}{\sqrt{1-\mathrm{x}^{2}}}\]
- \(\frac{\mathrm{e}^{\sin ^{-1} \mathrm{x}}}{\mathrm{x}}\)
Answer
(C) xe ^ ^ -1 x 1- x ^ 2
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