If x is very large, the value of (x^ 2 +16 ) - (x^ 2 +9 ) is
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If x is very large, the value of \(\sqrt{\left(x^{2}+16\right)}-\sqrt{\left(x^{2}+9\right)}\) is
- \(\frac{9}{x}\)
- \(\frac{7}{2 x}\)
- \(\frac{9}{2 x}\)
- none of these
Answer
(B) 7 2 x
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