For the reaction: array l X _ 2 O _ 4 (t) 2 XO _ 2 ( ~g ) U=2.1 k cal , S=20 cal ~K ^ -1…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
For the reaction:
\(\begin{array}{l} \mathrm{X}_{2} \mathrm{O}_{4}(t) \rightarrow 2 \mathrm{XO}_{2}(\mathrm{~g}) \\ \Delta U=2.1 \mathrm{k} \mathrm{cal}, \Delta S=20 \mathrm{cal} \mathrm{~K}{ }^{-1} \text { at } 300 \mathrm{~K} \end{array}\)
Hence \(\Delta \mathrm{G}\) is:
- 2.7 k cal
- -2.7 k cal
- 9.3 k cal
- -9.3 k cal
Answer
(B) -2.7 k cal
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