For the reaction : C _ ( s ) + O _ 2( ~g ) CO _ 2( ~g )
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
For the reaction :
\(\mathrm{C}_{(\mathrm{s})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})}\)
\(\mathrm{C}_{(\mathrm{s})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})}\)
- ∆H < ∆U
- ∆H > ∆U
- ∆H = ∆U
- ∆H = 0
Answer
(C) ∆ H = ∆ U
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