Heat of neutralization between HCl and NaOH is -13.7 kcal equiv -1 . Heat of…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
Heat of neutralization between HCl and NaOH is -13.7 kcal equiv-1. Heat of neutralization of H2C2O4 (oxalic acid) with NaOH is -26 kcal mole-1. Hence, heat of dissociation of H2C2O4 as:
\(H_{2} C_{2} O_{4}\) ⇌ \(\mathrm{ZH}^{+}+\mathrm{C}_{2} \mathrm{O}_{4}^{2-} .\) is:
- 12.3 kcal mole-1
- 1.4 kcal mole-1
- -39.7 kcal mole-1
- -12.3 kcal mole-1
Answer
(A) 12.3 kcal mole -1
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