If f(x)= e^ x 1+e^ x , t_ 1 = _ f(-a) ^ f(a) x g[x(1-x)] d x and d_ 2 = _ f(-a) ^ f(a)…
Mathematics · JEE Main · NTA Exams — Integral Calculus
If \(f(x)=\frac{e^{x}}{1+e^{x}}, t_{1}=\int_{f(-a)}^{f(a)} x g[x(1-x)] d x\)
and \(d_{2}=\int_{f(-a)}^{f(a)} g[x(1-x)] d x\).
Then, the value of \(\frac{I_{2}}{I_{1}}\) is
- 2
- - 3
- - 1
- 1
Answer
(D) 1
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