C is a point on the line segment joining A(–3, 4) and B (2, 1) such that AC = 2 BC then…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
C is a point on the line segment joining A(–3, 4) and
B (2, 1) such that AC = 2 BC then coordinates of C are
B (2, 1) such that AC = 2 BC then coordinates of C are
- \(\left(\frac{1}{3}, 2\right)\)

- (2, 7)
- (7, 2)
Answer
(A) ( 1 3 , 2 )
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The equation of the base of an equilateral triangle is x+y=2 and the vertex is (2, –1). Length of its side is…
- The equation of the tangent to the parabola y 2 = 4ax at point (a/t 2 , 2a/t) is
- The circles a x^ 2 +a y^ 2 +2 g_ 1 x+2 f_ 1 y+c_ 1 =0 and b x^ 2 +b y^ 2 +2 g_ 2 x+2 f_ 2 y+c_ 2 =0 (a 0 and…
- Equation of the ellipse whose foci are (4, 0) and (–4, 0) and e = 1/3 is
- The intercept on the line y = x by the circle x^ 2 +y^ 2 -2 x=0 is AB. Equation of the circle on AB as a…
- A point which divides the joint of (1, 2) and (3, 4) externally in the ratio 1 : 1
- The circles x 2 + y 2 + 2x – 2y + 1 = 0 and x 2 + y 2 – 2x – 2y + 1 = 0 touch each other
- The line joining (5, 0) to (10 cosθ, 10 sinθ) is divided internally in the ratio 2 : 3 at P. If θ varies then…
More Co-ordinate Geometry questions · Browse all practice questions