Electrons with De-Broglie's wavelength λ fall on the target in an X-ray tube. The cut-off…
Physics · JEE Main · NTA Exams — Dual Nature of Matter and Radiation
Electrons with De-Broglie's wavelength λ fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-rays is
- \(\lambda_{g}=\frac{2 m c \lambda^{2}}{h}\)
- \(\lambda_{a}=\frac{2 h}{m c}\)
- \(\lambda_{g}=\frac{2 m^{2} c^{2} \lambda^{3}}{h^{2}}\)
- \(\lambda_{!}=\lambda\)
Answer
(D) _ ! =
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