The energy E of a photon is equal to the kinetic energy of helium particle. If λ 1 is the…
Physics · JEE Main · NTA Exams — Dual Nature of Matter and Radiation
The energy E of a photon is equal to the kinetic energy of helium particle. If λ1 is the de-Broglie's wavelength of the helium particle and λ2 is the wavelength of the photon, the ratio λ1 / λ2 is proportional to
- E0
- E1/2
- E-1
- E-2
Answer
(B) E 1 /2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Given that a photon of light of wavelength 10,000 a A has energy equal to 1.23 eV. When light of wavelength…
- A particle moving with kinetic energy E has de Broglie wavelength . If energy E is added to its energy, the…
- In parallel plate capacitor arrangement having potential difference V_ B a radiation falls on the positive…
- Given below are two statements. STATEMENT - 1: A small metal ball is suspended in a uniform electric field…
- In the Davisson and Germer experiment, the velocity of electrons emitted from the electron gun can be…
- Electrons with De-Broglie's wavelength λ fall on the target in an X-ray tube. The cut-off wavelength of the…
- An electromagnetic wave of wavelength ' ' is incident on a photosensitive surface of negligible work…
- Photons of 5.5 eV energy falls on the surface of metal emitting photoelectrons of maximum kinetic energy 4.0…
More Dual Nature of Matter and Radiation questions · Browse all practice questions