1 x^ 2 -1 ( x-1 x+1 ) dx equals
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
\(\int \frac{1}{x^{2}-1} \ln \left(\frac{x-1}{x+1}\right) \mathrm{dx}\)equals
- \(\frac{1}{2} \ln \left(\frac{\mathrm{x}-1}{\mathrm{x}+1}\right)+\mathrm{c}\)
- \(\frac{1}{4} \ln ^{2}\left(\frac{\mathrm{x}-1}{\mathrm{x}+1}\right)+\mathrm{c}\)
- \(\frac{1}{2} \ln ^{2}\left(\frac{\mathrm{x}+1}{\mathrm{x}-1}\right)+\mathrm{c}\)
- \(\frac{1}{4} \ln ^{2}\left(\frac{\mathrm{x}+1}{\mathrm{x}-1}\right)+\mathrm{c}\)
Answer
(B) 1 4 ^ 2 ( x -1 x +1 )+ c, (D) 1 4 ^ 2 ( x +1 x -1 )+ c
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