The value of ^ -1 ( 1+ ^ 2 (2) -1 (2) )- ^ -1 ( 1+ ^ 2 ( 1 2 ) +1 ( 1 2 ) ) is equal to
Mathematics · JEE Main · NTA Exams — Trigonometry
The value of
\[\cot ^{-1}\left(\frac{\sqrt{1+\tan ^{2}(2)}-1}{\tan (2)}\right)-\cot ^{-1}\left(\frac{\sqrt{1+\tan ^{2}\left(\frac{1}{2}\right)}+1}{\tan \left(\frac{1}{2}\right)}\right)\]
is equal to
\[\cot ^{-1}\left(\frac{\sqrt{1+\tan ^{2}(2)}-1}{\tan (2)}\right)-\cot ^{-1}\left(\frac{\sqrt{1+\tan ^{2}\left(\frac{1}{2}\right)}+1}{\tan \left(\frac{1}{2}\right)}\right)\]
is equal to
Answer
(B)
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