If 1 [3] x+1 + x+1 d x=A-6 |(x+1)^ 1 6 +1 |+c , then A is equal to

Mathematics · JEE Main · NTA Exams — Integral Calculus

1. ^{\(2(x+1)^{5}-3(x+1)^{\frac{1}{3}}+6(x+1)^{\frac{1}{2}}\)}
2.  ^{\(2(x+1)^{\frac{1}{3}}-3(x+1)^{\frac{1}{2}}+6(x+1)^{\frac{1}{6}}\)}
3. ^{\(3(x+1)^{\frac{1}{3}}-2(x+1)^{\frac{1}{2}}+6(x+1)^{\frac{1}{6}}\)}
4. ^{\(2(x+1)^{\frac{1}{2}}-3(x+1)^{\frac{1}{3}}+6(x+1)^{\frac{1}{6}}\)}

Answer

(D) 2(x+1)^ 1 2 -3(x+1)^ 1 3 +6(x+1)^ 1 6

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