If the circle x 2 + y 2 – 2x – 2y + 1 = 0 is inscribed in a triangle whose two sides are…

Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry

1. \(\frac{1}{a}+\frac{1}{b}-1=-\sqrt{\frac{1}{a^{2}}+\frac{1}{b^{2}}}\)
2. \(\frac{1}{a}+\frac{1}{b}-1\) is negative
3. \(\frac{1}{a}+\frac{1}{b}>1\)
4. \(\frac{1}{a}+\frac{1}{b}-1=+\sqrt{\frac{1}{a^{2}}+\frac{1}{b^{2}}}\)

Answer

(A) 1 a + 1 b -1=- 1 a^ 2 + 1 b^ 2, (B) 1 a + 1 b -1 is negative

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