Given the points A (0, 4) and B (0,–4), the equation of the locus of the point P (x, y)…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
Given the points A (0, 4) and B (0,–4), the equation of the locus of the point P (x, y) such that |AP – BP| = 6 is :
- 9x2 – 7y2 + 63 = 0
- 9x2 – 7y2 – 63 = 0
- 7x2 – 9y2 + 63 = 0
- 7x2 – 9y2 – 63 = 0
Answer
(A) 9x 2 – 7y 2 + 63 = 0
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