Differentiate the function y= [x^ 2 +1 ] 2 x w. r. t. x.
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Differentiate the function \(y=\frac{\log \left[x^{2}+1\right]}{\cos 2 x}\) w. r. t. x.
- \(\frac{2 x \cos x-2 \sin 2 x\left[x^{2}+1\right] \log \left(x^{2}+1\right)}{\left[x^{2}+1\right] \cos ^{2} 2 x}\)
- \(\frac{2 \sin x-2 \sin 2 x\left[x^{2}+1\right] \log \left(x^{2}+1\right)}{\left[x^{2}+1\right] \cos ^{2} 2 x}\)
- \(\frac{2 x \cos 2 x+2 \sin 2 x\left[x^{2}+1\right] \log \left[x^{2}+1\right]}{\left[x^{2}+1\right] \cos ^{2} 2 x}\)
- None of these
Answer
(A) 2 x x-2 2 x [x^ 2 +1 ] (x^ 2 +1 ) [x^ 2 +1 ] ^ 2 2 x
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