The rate of change of the surface area of a sphere of radius r, when the radius is…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The rate of change of the surface area of a sphere of radius r, when the radius is increasing at the rate of 2 cm/s is proportional to
- \(\frac{1}{r}\)
- \(\frac{1}{\mathrm{r}^{2}}\)
- r
- r2
Answer
(C) r
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