The value of parameter a so that the line (3 – a) x + ay + (a 2 – 1) = 0 is normal to the…

Mathematics · JEE Main · NTA ExamsLimit, Continuity and Differentiability

The value of parameter a so that the line
(3 – a) x + ay + (a2 – 1) = 0 is normal to the curve xy = 1, may lie in the interval
  1. (−∞, 0)
  2. (1, 3)
  3. (0, 3)
  4. (3, ∞)

Answer

(A) (−∞, 0), (D) (3, ∞)

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