The time period of a simple pendulum measured inside a stationary lift is found to be T…
Physics · NEET · NTA Exams — Oscillations and Waves
The time period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with an acceleration g/3, the time–period is
- \(T \sqrt{3}\)
- \(\frac{T \sqrt{3}}{2}\)
- \(\frac{T}{\sqrt{3}}\)
- \(\frac{T}{3}\)
Answer
(B) T 3 2
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