A point mass oscillates along the x-axis according to the law x = x _ a ( t- / 4) . If…
Physics · NEET · NTA Exams — Oscillations and Waves
A point mass oscillates along the x-axis according to the law \(\mathbf{x}=\mathbf{x}_{\mathbf{a}} \cos (\omega t-\pi / 4)\). If the acceleration of the particle is written as \(a=A \cos (\omega t+\delta)\), then
- \(A=x_{0} \delta=-\pi / 4\)
- \(A=x_{0} \omega^{2}, \delta=\pi / 4\)
- \(A=x_{a} \omega^{2}, \delta=-\pi / 4\)
- \(A=x_{n} \omega^{2}, \delta=3 \pi / 4\)
Answer
(D) A=x_ n ^ 2 , =3 / 4
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