Given, E _ Fr ^ Ia ++ Fr =-0.036 ~V , E _ Fr ^ Ia ^ 2+ / Fr =-0.439 ~V The value of…

Chemistry · NEET · NTA ExamsElectrochemistry

Given,

\(\mathrm{E}_{\mathrm{Fr}}^{\mathrm{Ia}++\mathrm{Fr}}=-0.036 \mathrm{~V}, \mathrm{E}_{\mathrm{Fr}}^{\mathrm{Ia}}{ }^{2+} / \mathrm{Fr}=-0.439 \mathrm{~V}\)

The value of standard electrode potential for the change, \(\mathrm{Fe}^{3+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+}(\mathrm{aq})\) will be:

  1. - 0.072 V
  2. 0.385 V
  3. 0.770 V
  4. - 0.270 V

Answer

(C) 0.770 V

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Electrochemistry questions · Browse all practice questions