Given that array l E _ B _ 2^ / H _ 2 O ^ =1.23 ~V ; E _ I _ 2 O _ 8 ^ 2- / AO _ 4 ^ 2- ^…
Chemistry · NEET · NTA Exams — Electrochemistry
Given that \(\begin{array}{l}
\mathrm{E}_{\mathrm{B}_{2^{\prime} / \mathrm{H}_{2} \mathrm{O}}}^{\ominus}=1.23 \mathrm{~V} ; \mathrm{E}_{\mathrm{I}_{2} \mathrm{O}_{8}^{2-} / \mathrm{AO}_{4}^{2-}}^{\ominus}=2.05 \mathrm{~V} \\
\mathrm{E}_{\mathrm{Br}_{2^{\prime} / \mathrm{Ar}^{-}}}^{\ominus}=1.09 \mathrm{~V} ; \mathrm{E}_{\mathrm{AL}^{3+} / \mathrm{AL}}^{\ominus}=+1.4 \mathrm{~V}
\end{array}\)
The strongest oxidizing agent is
- \(5_{2} 0_{11}^{2-}\)
- O2
- Au3+
- Br2
Answer
(A) 5_ 2 0_ 11 ^ 2-
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