In the given reaction scheme, P is a phenyl alkyl ether, Q is an aromatic compound; R and…
Chemistry · JEE Advanced · NTA Exams — Alcohols, Phenols and Ethers
In the given reaction scheme, P is a phenyl alkyl ether, Q is an aromatic compound; R and S are themajor products. (2023)
\(\mathrm{P} \xrightarrow{\mathrm{HI}} \mathrm{Q} \xrightarrow[(\text { iii }) \mathrm{H}_{3} \mathrm{O}^{+}]{(\text {i }) \mathrm{NaOH}_{3}\left(\text { ii } \mathrm{CO}_{2}\right.} \mathrm{R} \xrightarrow[(\text { ii }) \mathrm{H}_{3} \mathrm{O}^{+}]{\text {(i) }\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right) \mathrm{O}} \mathrm{~S}\)
The correct statement about S is
\(\mathrm{P} \xrightarrow{\mathrm{HI}} \mathrm{Q} \xrightarrow[(\text { iii }) \mathrm{H}_{3} \mathrm{O}^{+}]{(\text {i }) \mathrm{NaOH}_{3}\left(\text { ii } \mathrm{CO}_{2}\right.} \mathrm{R} \xrightarrow[(\text { ii }) \mathrm{H}_{3} \mathrm{O}^{+}]{\text {(i) }\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right) \mathrm{O}} \mathrm{~S}\)
The correct statement about S is
- It primarily inhibits noradrenaline degrading enzymes.
- It inhibits the synthesis of prostaglandin.
- It is a narcotic drug.
- It is ortho-acetylbenzoic acid.
Answer
(B) It inhibits the synthesis of prostaglandin.
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