A cell of emf 1.5 V and internal resistance 2 is connected to two resistors of 5 and 8 in…
Physics · Class 12 · CBSE — Current Electricity
A cell of emf 1.5 V and internal resistance 2 \(\Omega\) is connected to two resistors of 5 \(\Omega\) and 8 \(\Omega\) in series. The potential difference across the 5 \(\Omega\) resistor will be:
- 3.3 V
- 1 V
- 0.5 V
- 0.33 V
Answer
(C) 0.5 V
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