The kinetic energy of one mole of a gas is given by the expression : K E = 3 PV 2 and…
Chemistry · JEE Advanced · NTA Exams — States of Matter (Gases and Liquids)
The kinetic energy of one mole of a gas is given by the expression :
\(\mathrm{K} \cdot \mathrm{E} \cdot=\frac{3 \mathrm{PV}}{2} \text { and K.E. }=\frac{3}{2} \mathrm{RT}\)
Hence, it can be said that
\(\mathrm{K} \cdot \mathrm{E} \cdot=\frac{3 \mathrm{PV}}{2} \text { and K.E. }=\frac{3}{2} \mathrm{RT}\)
Hence, it can be said that
- K.E. \(\propto\) P at constant temperature
- K.E. \(\propto\) T at constant pressure
- K.E. is not directly proportional to volume at constant temperature
- K.E. \(\propto\) V at constant temperature
Answer
(B) K.E. T at constant pressure, (C) K.E. is not directly proportional to volume at constant temperature
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