Let S 1, 2, 3, ..., 9 . For k = 1, 2, ..., 5, let N k be the number of subsets of S …
Mathematics · JEE Advanced · NTA Exams — Permutations and Combinations
Let S {1, 2, 3, ..., 9}. For k = 1, 2, ..., 5, let Nk be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N1 + N2 + N3 + N4 + N5 =
- 125
- 252
- 210
- 126
Answer
(D) 126
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