The continued product, 2 . 6 . 10 . 14 ........ to n factors is equal to :

Mathematics · JEE Advanced · NTA Exams — Permutations and Combinations

1. ²ⁿC_n
2. ²ⁿP_n
3. (n + 1) (n + 2) (n + 3) ....... (n + n)
4. none of these

Answer

(B) 2n P n, (C) (n + 1) (n + 2) (n + 3) ....... (n + n)

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